The correct options are
A A={2,3}
B B={3,4,5}
C (A−B)∩(B−A)=ϕ
D n((AΔB)×(BΔA))=9
If y<2⇒y={0,1}
x−2=y⇒x−2=0⇒x=2
x−2=1⇒x=3
A={2,3}
Now, x<3⇒x={0,1,2}
x+3=y⇒0+3=y⇒y=3
1+3=y⇒y=4
2+3=y⇒y=5
∴B={3,4,5}
Now, A−B={2},B−A={4,5}
(A−B)∩(B−A)=ϕ
AΔB=(A−B)∪(B−A)
={2,4,5}
n((AΔB)×(BΔA))=32=9