If A = {x: x = 2n+1, n ∈ N and 3 ≤ n ≤ 9},then the cardinality of A is .

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Solution

The correct option is C 7
The elements of A satisfy the condition that they are of the form $2 n + 1,$ where $n$ is a natural number between 3 and 9.
Hence, the cardinality of A is the number of natural numbers between 3 and 9, including 3 and 9.
This number is 7 as A = {7,9,11,13,15,17,19}.

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