If A - x - x - M - x is a factor of 6-1-2-3-6and B - x - x - N - x is a factor of 8-1-2-4-8- Then find-i A - Bii A - Biii A - Biv B - A

We have (i) A ∪ B={ 1,2, 3, 6 }∪{ 1,2,4,8 }={ 1,2,3,4,6,8 } (ii) A ∩ B={ 1,2, 3, 6 }∩{ 1,2,4,8 }={ 1,2 } (iii) A B={ 1,2, 3, 6 } { 1,2,4,8 }={ 3,6} (iv) B ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Universal Set

If A = x : x ...

Question

If A={ $x : x ϵ M$ , x is a factor of 6} $= {1, 2, 3, 6}$
and B={ $x : x ϵ N$ , x is a factor of 8} = ${1, 2, 4, 8}$ . Then find:

$(i) A \cup B$

$(i i) A \cap B$

$(i i i) A - B$

$(i v) B - A$

Open in App

Solution

We have

$(i) A \cup B = {1, 2, 3, 6} \cup {1, 2, 4, 8} = {1, 2, 3, 4, 6, 8}$

$(i i) A \cap B = {1, 2, 3, 6} \cap {1, 2, 4, 8} = {1, 2}$

$(i i i) A - B = {1, 2, 3, 6} - {1, 2, 4, 8} = {3, 6}$

$(i v) B - A = {1, 2, 4, 8} - {1, 2, 3, 6} = {4, 8}$

Suggest Corrections

Similar questions

Q. Let

A = \{x : x \in N\}, B = \{x : x - 2 n, n \in N\}, C = \{x : x = 2 n - 1, n \in N\}

and D = {x : x is a prime natural number}. Find:
(i)

A \cap B

(ii)

A \cap C

(iii)

A \cap D

(iv)

B \cap C

(v)

B \cap D

(vi)

C \cap D

Given A = ${x : x \in N a n d 3 < x \leq 6}$ and B = ${x : x \in W a n d x < 4}$ . Find : (i) Sets A and B in roster form (ii) $A \cup B$ (iii) $A \cap B$ (iv) A - B (v) B - A

Q. If

A = {3, 5}

and

A \times B = B \times A

, then the correct option(s) can be

Q. If

A = {x : x \in N, x < 6}

and

B = {x : x \in N, 3 < x < 8}

, then show that

A - B \neq B - A

with the help of Venn diagram.

A={x:x is the factor of 24,x belongs to N}

B={x:x is the prime number,x<30}

Then find AUB, A intersection B, A-B, B-A.

Join BYJU'S Learning Program

If A={x:xϵM, x is a factor of 6}={1,2,3,6} and B={x:xϵN, x is a factor of 8} = {1,2,4,8}. Then find: (i) A∪B (ii) A∩B (iii) A−B (iv) B−A

We have (i) A∪B={1,2,3,6}∪{1,2,4,8}={1,2,3,4,6,8} (ii) A∩B={1,2,3,6}∩{1,2,4,8}={1,2} (iii) A−B={1,2,3,6}−{1,2,4,8}={3,6} (iv) B−A={1,2,4,8}−{1,2,3,6}={4,8}

If A={ $x : x ϵ M$ , x is a factor of 6} $= {1, 2, 3, 6}$
and B={ $x : x ϵ N$ , x is a factor of 8} = ${1, 2, 4, 8}$ . Then find:

$(i) A \cup B$

$(i i) A \cap B$

$(i i i) A - B$

$(i v) B - A$

We have

$(i) A \cup B = {1, 2, 3, 6} \cup {1, 2, 4, 8} = {1, 2, 3, 4, 6, 8}$

$(i i) A \cap B = {1, 2, 3, 6} \cap {1, 2, 4, 8} = {1, 2}$

$(i i i) A - B = {1, 2, 3, 6} - {1, 2, 4, 8} = {3, 6}$

$(i v) B - A = {1, 2, 4, 8} - {1, 2, 3, 6} = {4, 8}$