If $A = {x : x$ is a factor of $72}$ , $B = {x : x$ is a multiple of $4 < 41}$ .Find $(A - B) \cup (B - A)$ ?

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Solution

$G i v e n, A = {x : x i s a f a c t o r o f 72} ∴ A = {1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 72} B = {x : x i s a m u l t i p l e o f 4 < 41} ∴ B = {4, 8, 12, 16, 20, 24, 28, 32, 36, 40} = {1, 2, 3, 6, 9, 18, 72} a n d (B - A) = {16, 20, 28, 32, 36, 40} ∴ (A - B) \cup (B - A) = {1, 2, 3, 6, 9, 16, 18, 20, 28, 32, 36, 40, 72}$

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