If $A = {x : x i s a m u l t i p l e o f 3} a n d B = {x : x i s a m u l t i p l e o f 5} .$ Then, $A \cap B$ is given by

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Solution

Finding the value of $A \cap B$ :
Given $A = {x : x i s a m u l t i p l e o f 3} a n d B = {x : x i s a m u l t i p l e o f 5} .$
$M u l t i p l e s o f 3 = {3, 6, 9, 12, 15, 18, 21, \dots .} A = {3, 6, 9, 12, 15, 18, 21, \dots .} M u l t i p l e s o f 5 = 5, 10, 15, 20, 25, 30 \dots . B = {5, 10, 15, 20, 25, 30 \dots .} A \cap B = {15, 30 \dots \dots .}$
Hence the value of $A \cap B i s {15, 30 \dots \dots .} .$

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