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Byju's Answer

Standard XII

Mathematics

Union

If A = x : x ...

Question

If A = {x: x is a natural number}

B = {x: x is even natural number}

C = {x: x is prime number}

Then (A ∪ B)∩ C =

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A ∩ B

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Solution

The correct option is D
C

A = {1, 2, 3, 4, - - - -}

B = {2, 4, 6, 8, - - - -}

C = {2, 3, 5, 7, 11, 13, - - - -}

A ∪ B = {1, 2, 3, - - - -} ∪ {2, 4, 6, 8, - - - -} = {1, 2, 3, - - - -} = A

(A ∪ B)∩ C = A ∩ C = {1, 2, 3, - - - -} ∩ {2, 3, 5, 7, - - - -} = C

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Similar questions

If A = {x: x is a natural number}

B = {x: x is an even natural number}

C = {x: x is a prime number}

Then (A $\cup$ B) $\cap$ C =

If A = {x : x is a natural number}

B = {x : x is an even natural number}

C = {x : x is a prime number}, then (A ∪ B) ∩ C = ______________ .

If A = {x: x is a natural number}, B ={x: x is an even natural number}

C = {x: x is an odd natural number} and D = {x: x is a prime number}, find

(i) A ∩ B

(ii) A ∩ C

(iii) A ∩ D

(iv) B ∩ C

(v) B ∩ D

(vi) C ∩ D

Q. If

A = {x : x

is a natural number

}, B = {x : x

is an even natural number

} C = {x : x

is an odd natural number

}

and

D = {x : x

is a prime number

},

find
(i)

A \cap B

(ii)

A \cap C

(iii)

A \cap D

(iv)

B \cap C

(v)

B \cap D

(vi)

C \cap D

Q. If

A = {x : x i s a n a t u r a l n u m b e r}, B = {x : x i s e v e n n a t u r a l n u m b e r},

C - {x : x i s a n o d d n a t u r a l n u m b e r}

and

D = {x : x i s a' n u m b e r}

find

C \cap D

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If A = {x: x is a natural number} B = {x: x is even natural number} C = {x: x is prime number} Then (A ∪ B)∩ C =

The correct option is D C A = {1, 2, 3, 4, - - - -} B = {2, 4, 6, 8, - - - -} C = {2, 3, 5, 7, 11, 13, - - - -} A ∪ B = {1, 2, 3, - - - -} ∪ {2, 4, 6, 8, - - - -} = {1, 2, 3, - - - -} = A (A ∪ B)∩ C = A ∩ C = {1, 2, 3, - - - -} ∩ {2, 3, 5, 7, - - - -} = C

If A = {x: x is a natural number}

B = {x: x is even natural number}

C = {x: x is prime number}

Then (A ∪ B)∩ C =

The correct option is D
C

A = {1, 2, 3, 4, - - - -}

B = {2, 4, 6, 8, - - - -}

C = {2, 3, 5, 7, 11, 13, - - - -}

A ∪ B = {1, 2, 3, - - - -} ∪ {2, 4, 6, 8, - - - -} = {1, 2, 3, - - - -} = A

(A ∪ B)∩ C = A ∩ C = {1, 2, 3, - - - -} ∩ {2, 3, 5, 7, - - - -} = C