If $A = x : x is a natural number B = x : x is even natural number C = x : x is prime number$

Then, $(A \cup B) \cap C =$

$A$

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$A \cap B$

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$B$

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$C$

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Solution

The correct option is D
$C$

A = {1, 2, 3, 4, - - - -}
B = {2, 4, 6, 8, - - - -}
C = {2, 3, 5, 7, 11, 13, - - - -}

A ∪ B ={1, 2, 3, - - - -} ∪ {2, 4, 6, 8, - - - -}
= {1, 2, 3, - - - -} = A

(A ∪ B) ∩ C = A ∩ C
= {1, 2, 3, - - - -} ∩ {2, 3, 5, 7, - - - -} = C

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Similar questions

If $A = x : x is a natural number B = x : x is even natural number C = x : x is prime number$

Then, $(A \cup B) \cap C =$

A = {x : x i s a n a t u r a l n u m b e r}

⟹

State, Whether the following statements are true of false.

(i) If $a < b, t h e n a - c < b - c$

(ii) If $a > b, t h e n a + c > b + c$

(iii) If $a < b, t h e n a c > b c$

(iv) If $a > b, t h e n \frac{a}{c} < \frac{b}{c}$

(v) If $a - c > b - d; t h e n a + d > b + c$

(vi) If $a < b, a n d c > 0, t h e n a - c > b - c where a, b, c and are real numbers and c \neq 0.$

A, B, C

D

A \subseteq B

B \subseteq D

A \subseteq C

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