If A - x - y - x 2- y 2-25- And B - x - y - x 2-9 y 2-144- then A - B containsA- One pointB- Three pointsC- Four pointsD- Two points

The correct option is C Four points A = Set of all values (x,y) : x^2 + y^2 = 25 = 5^2 B = x^2/144 + y^2/16 = 1 i.e., x^2/(12)^2 + y^2/(4)^2 = 1 Clearly ...

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Byju's Answer

Standard VIII

Mathematics

Intersection of Sets

If A =[ x , y...

Question

If $A = [(x, y) : x^{2} + y^{2} = 25]$ And $B = [(x, y) : x^{2} + 9 y^{2} = 144], t h e n A \cap B$ contains

One point

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Three points

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Two points

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Four points

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Solution

The correct option is D
Four points

A = Set of all values (x,y) : $x^{2} + y^{2} = 25 = 5^{2}$

B = $\frac{x^{2}}{144} + \frac{y^{2}}{16} = 1$ i.e., $\frac{x^{2}}{(12)^{2}} + \frac{y^{2}}{(4)^{2}} = 1$

Clearly , $A \cap B$ consists of four points.

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If A=[(x,y):x2+y2=25] And B=[(x,y):x2+9y2=144], then A∩B contains

The correct option is D Four points A = Set of all values (x,y) : x2+y2=25=52 B = x2144+y216=1 i.e., x2(12)2+y2(4)2=1 Clearly , A∩B consists of four points.

If $A = [(x, y) : x^{2} + y^{2} = 25]$ And $B = [(x, y) : x^{2} + 9 y^{2} = 144], t h e n A \cap B$ contains

The correct option is D
Four points

A = Set of all values (x,y) : $x^{2} + y^{2} = 25 = 5^{2}$

B = $\frac{x^{2}}{144} + \frac{y^{2}}{16} = 1$ i.e., $\frac{x^{2}}{(12)^{2}} + \frac{y^{2}}{(4)^{2}} = 1$

Clearly , $A \cap B$ consists of four points.