If A={(x,y):x2+y2=25} and B={(x,y):x2+9y2=144}; then A∩B contains
A
one point
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B
three points
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C
two points
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D
four points
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Solution
The correct option is D four points Clearly, A is the set of all points on the circle x2+y2=25 and B is the set of all points on the ellipse x2+9y2=144. These two intersect at four points P,Q,R and S. Hence, A∩B contains four points.