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If A = y:y=lo...
Question
If
A
=
{
y
:
y
=
log
2
|
x
−
2
|
,
x
<
5
,
x
is a whole number
}
,
B
=
{
y
:
y
=
|
x
−
2
|
,
x
∈
[
0
,
1
]
,
y
∈
N
}
,
C
=
{
1
,
3
,
5
}
, then
n
(
(
A
×
B
)
∩
(
B
×
C
)
)
is
Open in App
Solution
Given:
A
=
{
y
:
y
=
log
2
|
x
−
2
|
,
x
<
5
,
x
is a whole number
}
,
B
=
{
y
:
y
=
|
x
−
2
|
,
x
∈
[
0
,
1
]
,
y
∈
N
}
,
C
=
{
1
,
3
,
5
}
log
2
|
x
−
2
|
is not defined for
x
=
2
now for
x
=
0
,
1
,
3
,
4
|
x
−
2
|
=
2
,
1
,
1
,
2
∴
A
=
{
0
,
1
}
y
=
|
x
−
2
|
,
x
∈
[
0
,
1
]
⇒
y
∈
{
1
,
2
}
(
∵
y
∈
N
)
⇒
B
=
{
1
,
2
}
C
=
{
1
,
3
,
5
}
(
A
×
B
)
∩
(
B
×
C
)
=
(
A
∩
B
)
×
(
B
∩
C
)
=
{
(
1
,
1
)
}
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0
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If A ={(x : x ∈ W, x < 2}, B = {x : x ∈ N, 1 < x < 5} and C = 3, 5, then A × (B ∩ C) = _________.
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,
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≠
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and
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,
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∈
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∩
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Q.
If
A
=
{
y
:
y
=
log
2
|
x
−
2
|
,
x
<
5
,
x
is a whole number
}
,
B
=
{
y
:
y
=
|
x
−
2
|
,
x
∈
[
0
,
1
]
,
y
∈
N
}
,
C
=
{
1
,
3
,
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}
, then
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∩
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)
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is
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