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Highest Power of a Number

If a1=1 and a...

Question

If a₁ = 1 and a_n+1 – 3a_n + 2 = 4n for every positive integer n, then a₁₀₀ equals

3⁹⁹ – 200

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3⁹⁹ + 200

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3¹⁰⁰ – 200

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3¹⁰⁰ + 200

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3⁹⁹-100

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Solution

The correct option is C 3¹⁰⁰ – 200
option (c)
Write options as
a) 3^n-1- 2n,
b) 3^n-1+ 2n,
c) 3ⁿ- 2n,
d) 3ⁿ+ 2n,
e) 3^n-1-n
Check for n = 1, a_n=1

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