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Nature of Roots

If a 2+b 2 x ...

Question

If $(a^{2} + b^{2}) x^{2} + 2 (a b + b d) x + c^{2} + d^{2} = 0$ has no real roots, then

(a) ab = bc
(b) ab = cd
(c) ac = bd
(d) ad ≠ bc

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Solution

The given quadric equation is , and roots are equal.

Here,

As we know that

Putting the value of

The given equation will have no real roots, if

Thus, the correct answer is

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Similar questions

Q. If the equations

(a^{2} + b^{2}) x^{2} - 2 (a c + b d) x + c^{2} + d^{2} = 0

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