If a2b3c = 256/27 find min value of a + b + c, given a, b, c are positive real nos
Solution:option d
Take numbers as a/2, a/2, b/3, b/3, b/3,c
Now apply AM>GM on these six numbers.
We have a2b3c = 256/27. Solving we get min value of a+b+c as 4. Hence correct option: d