If $a b = 1, b c = 2$ and $a c = 8$ , what is the value of $a b c$ ?

2

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Solution

The correct option is B $4$
Let us multiply the given values $a b = 1, b c = 2$ and $a c = 8$ as shown below:

$a b \times b c \times a c = 1 \times 2 \times 8 \Rightarrow a^{2} b^{2} c^{2} = 16 \Rightarrow (a b c)^{2} = 16 \Rightarrow a b c = \sqrt{16} \Rightarrow a b c = 4$

Hence, the value of $a b c$ is $4$ .

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