If AB = 10 cm & DB = 40 cm (diameter). What is the radius of curvature & focal length?
20 cm, 10 cm
Since the diameter is equal to 40 cm then the radius of curvature is equal to half of it. Centre of curvature = radius of curvature = 20 cm. The focus is point A since parallel rays pass through point A. So, AB = focal length = 10 cm.