If AB = 10 cm & DB = 40 cm (diameter). What is the radius of curvature & focal length of the spherical glass?
20 cm, 10 cm
Given:
Diameter of the sphere = DB = 40 cm.
Radius of curvature (DO or OB) is half of diameter of curvature (DB) = 20 cm.
Focus is at point A since parallel rays after reflection pass through point A.
Focal length (f) is half of the radius of curvature (R)
∴ f=R2
=202=10 cm