Question

If AB = 6 m, Find the Perimeter of the $△$ ADB.

• A. 8 + $\sqrt{3}7$ m
• B. 7 + $\sqrt{3}9$ m
• C. 7 + $\sqrt{3}7$ m
• D. 9 + $\sqrt{3}7$ m

Answer 1

The correct option is C

7 + $\sqrt{3}7$ m

AD and AB are given. We can find BD using Pythagoras theorem.

BD = $\sqrt{A{D}^2+A{B}^2}$

BD = $\sqrt{1^2+6^2}$

= $\sqrt{1+36}$ = $\sqrt{3}7$ m

$\therefore$ Perimeter of the $△$ ABD = AD + AB + BD = 1 + 6+ $\sqrt{3}7$

= 7 + $\sqrt{3}7$ m