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Byju's Answer
Standard XII
Mathematics
Transpose of a Matrix
If A B=A and ...
Question
If AB = A and BA = B, where A and B are square matrices, then
(a) B
2
= B and A
2
= A
(b) B
2
≠ B and A
2
= A
(c) A
2
≠ A, B
2
= B
(d) A
2
≠ A, B
2
≠ B
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Solution
(a) B
2
= B and A
2
= A
Here
,
A
B
=
A
.
.
.
1
B
A
=
B
.
.
.
2
⇒
A
B
A
=
A
A
Multiplying
both
sides
by
A
B
A
B
=
B
B
Multiplying
both
sides
by
A
⇒
A
B
=
A
2
From
eq
.
2
B
A
=
B
2
From
eq
.
1
⇒
A
=
A
2
From
eq
.
1
B
=
B
2
From
eq
.
2
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0
Similar questions
Q.
If A and B are square matrices of the same order, then (A + B)(A − B) is equal to
(a) A
2
− B
2
(b) A
2
− BA − AB − B
2
(c) A
2
− B
2
+ BA − AB
(d) A
2
− BA + B
2
+ AB
Q.
Show that if A and B are square matrices such that AB = BA, then
(
A
+
B
)
2
=
A
2
+
2
A
B
+
B
2
.
Q.
If A and B are square matrices of the same order, explain, why in general
(i) (A + B)
2
≠ A
2
+ 2AB + B
2
(ii) (A − B)
2
≠ A
2
− 2AB + B
2
(iii) (A + B) (A − B) ≠ A
2
− B
2
.
Q.
If
A
,
B
are two matrices and
A
B
=
B
,
B
A
=
A
, then
A
2
+
B
2
Q.
If A and B are square matrices of the same order such that AB = BA, then show that (A + B)
2
= A
2
+ 2AB + B
2
.
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