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Question

If AB,AC,PQ are tangents in given fig. and AB=5 cm, find the perimeter of ΔAPQ.
971263_9c29383927c84bd8899d682530f48c28.png

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Solution

Given AB=5 cm
we know that From a point we can draw two equal tangent on the circle
hence AB=AC=5 cm
And Also, PB=PX
and QC=QX........(1)
Again AB=AC=5
AP+PB=AQ+QC=5
AP+PX=AQ+QX=5 [From eqn (1)]
Perimeter of triangle APQ
p=AP+PQ+AQ
p=(AP+Px)+(QX+AQ)
p=5+5
p=10 cm

1441179_971263_ans_ab31d598840a418f86e4c898f96fe145.png

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