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Question

If AB and AC are two chords of a circle of radius 5 cm such that AB=AC=45 cm, then the length of the chord BC is

A
8 cm
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B
8.4 cm
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C
9 cm
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D
None of these
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Solution

The correct option is B 8 cm
Let OM=x.
Then, x2+(112)2=r2
and (x+3)2+(52)2=r2
Theb, x2+6x+9+254=x2+1214
6x=15
x=2.5cm
Thus, r2=(2.5)2+1214=1464
r=1462cm

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