If AB and CD are two equal chords of a circle with centre O such that $∠ A O B = 80^{\circ}$ , then find $∠ C O D$ .

40^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

80^{\circ}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

120^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $80^{\circ}$
$∠ C O D = ∠ A O B = 80^{\circ}$
Equal chords of the circle subtend equal angles at the centre

Suggest Corrections

Similar questions

∠ A O B = 75^{\circ}

∠ C O D

25^{\circ}

If $A B, B C,$ and $C D$ are equal chords of a circle with $O$ as center, and $A D$ diameter then $∠ A O B$ equals to

In the adjoining figure, BC is a diameter of a circle with centre O. If AB and CD are two chords such that AB || CD, prove that AB = CD.

Join BYJU'S Learning Program