Question

If AB || CD and XY is transversal which meets AB at M and CD at N also $\angle AMX={62}^{\circ }$, then $\angle DNY=$.

• A. ${62}^{\circ }$
• B. ${118}^{\circ }$
• C. ${122}^{\circ }$

Answer 1

The correct option is A ${62}^{\circ }$


Given $\angle AMX={62}^{\circ }$
Therefore $\angle BMY={62}^{\circ }$ (vertically opposite angles)
$\angle BMY=\angle DNY$ (corresponding angles)
So $\angle DNY={62}^{\circ }$