If AB || DE, ∠AOD = 50° and ∠DPC = 160°, find the value of ∠DBE?

Open in App

Solution

Application of Properties : 2 Marks
Steps : 1 Mark
Correct answer : 1 Mark

$∠ P C E$ = 160 $^{o}$ – 90 $^{o}$ = 70 $^{o}$ (Exterior Angle Property)
In triangle ABC, $∠ C A B$ = 180 $^{o}$ – (90 $^{o}$ + 70 $^{o}$ )= 20 $^{o}$ (Angle Sum Property)
$∠ O B A$ = 50 $^{o}$ – 20 $^{o}$ = 30 $^{o}$ (Exterior Angle Property)
$∠ D B E$ = 90 $^{o}$ – 30 $^{o}$ = 60 $^{o}$

Suggest Corrections

Similar questions

If AB || DE, ∠AOD = $50^{\circ}$ and ∠DPC = $160^{\circ}$ , find the value of ∠DBE?

(a) If AB || DE, ∠AOD = 50° and ∠DPC = 160°, find the value of ∠DBE?

(b) A 15 m long ladder reached a window 12 m high from the ground when placed against a wall at a distance 'a'. Find the distance of the foot of the ladder from the wall.

[4 MARKS]

Q. The diagonals

A C

and

B D

of a rectangle

A B C D

intersects each other at

P

. If

∠ A B D = 50^{o}

, find

∠ D P C

Q. Given that ,

∠ A B D = 30^{o}, ∠ E B F = 40^{o}, ∠ F B C = 30^{o}

, then find

∠ D B E

Q. The diagonals AC and BD of a rectangle ABCD intersect each other at P. If ∠ABD = 50°, then ∠DPC =

(a) 70°

(b) 90°

(c) 80°

(d) 100°

Join BYJU'S Learning Program

If AB || DE, ∠AOD = 50° and ∠DPC = 160°, find the value of ∠DBE?

Application of Properties : 2 Marks Steps : 1 Mark Correct answer : 1 Mark ∠PCE = 160o – 90o = 70o (Exterior Angle Property) In triangle ABC, ∠CAB = 180o – (90o + 70o )= 20o (Angle Sum Property) ∠OBA = 50o – 20o = 30o (Exterior Angle Property) ∠DBE = 90o – 30o = 60o