If A→×B→=A→·B→, then angle between A→ and B→ will be
30°
45°
60°
90°
Find the angle between vector A→ and B→:
Given, A→×B→=A→·B→
⇒ ABsinθ=ABcosθ
⇒ tanθ=1
∴θ=45°
Hence, option ‘B’ is Correct.