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Question

If AB=i2j6k,BC=2ij+k,AC=i3j5k. then B=

A
cos1(4041)
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B
cos1(641)
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C
cos1(641)
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D
cos1(6263)
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Solution

The correct option is A cos1(641)
cosB=|a1b1+a2b2+a3b3a21+a22+a23b21+b22+b23|

=|2+261+4+364+1+1|

=|6416|

=641

B=cos1(641)

Option B is correct

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