If AB is a chord of a circle with centre O. If ∠AOB=50∘ and AB = 18 cm, then find the diameter of the circle. sin 25∘=0.42
Draw diameter AC passing through center O.
∠BOC=180−50∘=130∘
∠OBC=∠OCB=(180∘−130∘)2= 25∘
In right-angled triangle ABC
sin 25∘=ABAC
AC=ACsin25∘=180.42=42.85
So, diameter AC=42.85cm