If AB is perpendicular bisector of CD at P then

CD = BD

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AP = PB

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AC = AD

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CP = PD

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Solution

The correct option is D CP = PD

CP = PD

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Similar questions

If AE = BE, then CD is the perpendicular bisector of line segment AB.

If AB is perpendicular bisector of CD at P then

If AE = BE and $∠ D E B = 90^{\circ}$ , then CD is the perpendicular bisector of line segment AB.

A B C D, A B = A D

C B = C D

A C

B D

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