If AB is the object and CD is the image formed- If AP is the object distance and CP is the image distance from the mirror- Then choose the correct sign convention- begin array - hline3- height - of - object - ve - 4- height - of v object - - velllhline 5 - - AP - ve - 6 - - AP - velllhline7 - - PC - ve - 7 - - PC - velll hline array A- concave mirror - 1-3-5 - 7 - plane mirror - 1-3-5-7B- concave mirror -2-3-6 - 8- plane mirror -1-3-6-7C- concave mirror -2-3-6 - 8- plane mirror -1-3-6-8D- concave mirror -2-3-5-7- plane mirror -1-3-6-

The correct option is B concave mirror 2, 3, 6 amp; 8, plane mirror 1, 3 , 6 , 7 ...

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Standard X

Physics

Sign Convention for Ray Diagram

If AB is the ...

Question

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. h e i g h t o f i m a g e = + v e & 2. h e i g h t o f i m a g e = - v e 3. h e i g h t o f o b j e c t = + v e & 4. h e i g h t o f o b j e c t = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 7. P C = + v e \end{matrix}$

concave mirror - 1, 3, 5 & 7, plane mirror - 1, 3, 5, 7

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concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7

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concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3, 6, 8

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concave mirror - 2, 3, 5, 7, plane mirror - 1, 3, 6,

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Solution

The correct option is B
concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7

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Similar questions

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. height of image = + v e & 2. height of image = - v e 3. height of object = + v e & 4. height of object = - v e 5. AP = + v e & 6. A P = - v e 7. PC = + v e & 7. P C = + v e \end{matrix}$

Q. If AB is the object and CD is the image formed. If AP is the object distance and PC is the image distance from the mirror. Then choose the correct sign convention?
Assume that the object is beyond the focus in the case of concave mirror and new cartesian sign convention.

1. CD: Positive
2. CD: Negative
3. AB: Positive
4. AB: Negative
5. AP: Positive
6. AP: Negative
7. CP: Positive
8. CP: Negative

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. h e i g h t o f i m a g e = + v e & 2. h e i g h t o f i m a g e = - v e 3. h e i g h t o f o b j e c t = + v e & 4. h e i g h t o f o b j e c t = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 8. P C = - v e \end{matrix}$

Q. An object is placed at a distance of

2 f

from a concave mirror. Light reflected from the mirror falls on a plane mirror. The distance of the plane mirror from the concave mirror equals

f

. The distance of the final image from the concave mirror (due to reflection at both concave and plane mirror) is :

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If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention? 1. height of image=+ ve2. height of image=−ve3. height of object=+ve4. height of object=−ve5. AP=+ve6. AP=−ve7. PC=+ve7. PC=+ve

The correct option is B concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7

The correct option is B
concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7