If AB is the object and CD is the image formed. If AP is the object distance and PC is the image distance from the mirror. Then choose the correct sign convention?
Assume that the object is beyond the focus in the case of concave mirror and new cartesian sign convention.

1. CD: Positive
2. CD: Negative
3. AB: Positive
4. AB: Negative
5. AP: Positive
6. AP: Negative
7. CP: Positive
8. CP: Negative

Concave mirror - 1, 3, 5, 7
Plane mirror - 1, 3, 5, 7

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Concave mirror - 2, 3, 6, 8
Plane mirror - 1, 3, 6, 7

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Concave mirror - 2, 3, 6, 8
Plane mirror - 1, 3, 6, 8

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Concave mirror - 2, 3, 5, 7
Plane mirror - 1, 3, 6, 8

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Solution

The correct option is B Concave mirror - 2, 3, 6, 8
Plane mirror - 1, 3, 6, 7
Object distance is taken as negative always. So, AP is negative for both mirrors. (Concave mirror - 6, Plane mirror - 6)
Also, object size is taken as positive always. So, AB is positive for both mirrors (Concave mirror - 3, Plane mirror - 3)

For a plane mirror,

Image is erect. So, CD is positive. (Plane mirror- 1)

For a plane mirror, image is on the opposite side of the mirror to the object. So, CP is positive.(Plane mirror- 7)

For a concave mirror, when object is beyond focus:

Image is inverted. So, CD is negative. (Cocave mirror- 2)

For a plane mirror, image is on the same side of the mirror to the object. So, CP is negative. (Concave mirror- 8)

Compiling all, we get:
Plane mirror- 1, 3, 6, 7
Concave mirror- 2, 3, 6, 8

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