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Question

Question 2
If AB = QR, BC+PR and CA = PQ, then
(A) ΔABCΔPQR
(B) ΔCBAΔPQR
(C) ΔBACΔBCA
(D) ΔPQRΔBCA

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Solution

We know that, if ΔRST is congruent to ΔUVM i.e., ΔRSTΔUVW, then sides of ΔRST fall on corresponding equal sides of ΔUVW and angles of ΔRST fall on corresponding equal angles of ΔUVW

Here, given AB = QR, BC = PR and CA = PQ, which shows that AB covers QR, BC covers PR and CA covers PQ i.e., A correspond to Q, B correspond to R and C correspond to P
Or AQ,BR,CP
ΔABC=ΔQRP, so option (a) is incorrect
or ΔBACΔRQP, so option (c) is incorrect
or ΔCBAΔPRQ, so option (b) is correct
or ΔBCAΔRPQ. So option (d) is incorrect.


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