If $a b \times c d = 3337$ and $b a \times c d = 799,$ find the value of $(a b + c d)$ given that ab, ba and cd are all two digit positive integers.

117

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118

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119

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Solution

The correct option is B 118
$1^{s t}$ Method: - $71 \times 47 = 3337$ and $17 \times 47 = 799$ , so $a b + c d = 118$ (Option b).

$2^{n d}$ Method: - Odd $\times$ Odd = Odd and Odd + Odd = Even.

From the question we can conclude that all the four numbers are odd numbers. So the required answer has to be even, only option (b) is even.

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If ab×cd=3337 and ba×cd=799, find the value of (ab+cd) given that ab, ba and cd are all two digit positive integers.

The correct option is B 1181st Method: - 71×47=3337 and 17×47=799, so ab+cd=118 (Option b). 2nd Method: - Odd × Odd = Odd and Odd + Odd = Even. From the question we can conclude that all the four numbers are odd numbers. So the required answer has to be even, only option (b) is even.

If $a b \times c d = 3337$ and $b a \times c d = 799,$ find the value of $(a b + c d)$ given that ab, ba and cd are all two digit positive integers.