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Byju's Answer
Standard XII
Physics
Thermal Expansion
If abc=1 an...
Question
If
a
b
c
=
1
and
A
=
a
b
c
c
a
b
b
c
a
is an orthogonal matrix then
COLUMN-I
COLUMN-II
A) The value of
a
+
b
+
c
can be
P)
−
1
B) The value of
a
b
+
b
c
+
c
a
is
Q)
0
C) The value of
a
2
+
b
2
+
c
2
is
R)
1
D) The value of
a
3
+
b
3
+
c
3
S)
2
Open in App
Solution
A
=
a
b
c
c
a
b
b
c
a
is orthogonal matrix
A
A
T
=
I
=
A
T
A
a
1
a
2
a
3
b
1
b
2
b
3
c
1
c
2
c
3
is orthogonal
and if
a
=
a
1
^
i
+
a
2
^
j
+
a
3
^
k
b
=
b
1
^
i
+
b
2
^
j
+
b
3
^
k
c
=
c
1
^
i
+
c
2
^
j
+
c
3
^
k
then
|
a
|
=
1
|
b
|
=
1
|
c
|
=
1
a
.
b
=
b
.
c
=
c
.
a
=
0
hence
a
1
=
b
2
=
c
3
=
a
a
2
=
b
3
=
c
1
=
b
a
3
=
b
1
=
c
2
=
c
a
2
+
b
2
+
c
2
=
1
and
a
b
+
b
c
+
a
c
=
1
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0
Similar questions
Q.
Value of
a
3
+
b
3
+
c
3
−
3
a
b
c
a
b
+
b
c
+
c
a
−
a
2
−
b
2
−
c
2
, when
a
=
−
5
,
b
=
−
6
,
c
=
10
is
Q.
If a, b, c are distinct and
(
a
,
a
2
,
a
3
+
1
)
,
(
b
,
b
2
,
b
3
+
1
)
,
(
c
,
c
2
,
c
3
+
1
)
are linearly dependent, then value of abc is
Q.
Find the value of
a
3
+
b
3
+
c
3
−
3
a
b
c
a
b
+
b
c
+
c
a
−
a
2
−
b
2
−
c
2
, when
a
=
−
5
,
b
=
−
6
,
c
=
10
.
Q.
If the points
(
a
3
a
−
1
,
a
2
−
3
a
−
1
)
,
(
b
3
b
−
1
,
b
2
−
3
b
−
1
)
,
(
c
3
c
−
1
,
c
2
−
3
c
−
1
)
are collinear for three distinct values of
a
,
b
,
c
, then show that
a
b
c
−
(
b
c
+
c
a
+
a
b
)
+
3
(
a
+
b
+
c
)
=
0.
Q.
if a+b+c=6 , a
2
+b
2
+c
2
=14 and a
3
+b
3
+c
3
=36 then find the value of (abc) ?
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