If $A B C$ and $B D E$ are two equilateral triangles such that $D$ is the mid-point then find $a r (△ A B C) : a r (△ B D E)$ .

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Solution

Let us consider the problem:

Hence,
Area of triangle $= {(s i d e)}^{2} \times \frac{\sqrt{3}}{4}$
Therefore the ratio will be $4 : 1$

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ABC and BDE are two equilateral triangles such that D is the mid point of BC.Find the areas of triangles ABC and BDE

IF ABC and BDE are two equlateral triangles such that D is the mid point of BC, then find ar $(△ A B C) : a r (△ B D E) .$

A B C

B D E

A (Δ B D E)

x A (Δ A B C)

x

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