If ▲ABC and ▲DEF are two triangles such that AB/DF=BC/FD=CA/DE=3/4,then find ar(▲DEF):ar(▲ABC)

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Solution

$Since we know that if two triangles are simiar then, ratio of sides of two triangles are equal . From the given rati we can say that △ DFE ~ △ ABC And ratio of area is \frac{Area of △ DEF}{Area of △ ABC} = {[\frac{AB}{DF}]}^{2} = \frac{9}{16}$

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