If ∆ABC~∆DEF, AB=4cm, DE=6, EF=9cm and FD=12cm , then find the perimeter of ∆ABC.
Find the required perimeter:
Given : ∆ABC~∆DEF
So,
ABED=BCEF=ACDF⇒46=BC9=AC12
Considering the first two terms,
46=BC9⇒4×96=BC
⇒BC=6cm
Considering the last two terms,
BC9=AC12⇒12×69=AC
⇒AC=8cm
Perimeter of ∆ABC=AB+BC+AC
Perimeter of ∆ABC=4+6+8
Perimeter of ∆ABC=18cm
Hence, Perimeter of ∆ABC is 18cm.
In ΔABC and A DEF, it is being given that: AB = 5 cm, BC = 4 cm and CA = 4.2 cm; DE. 10cm, EF= 8cm and FD = 8.4cm. If AL⊥BD and DM⊥EF, find AL : DM.