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Standard X

Mathematics

Pythagoras Theorem

If A B C ∼ D ...

Question

If ∆ABC ∼ ∆DEF such that 2 AB = DE and BC = 6 cm, find EF.

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Solution

$∵$ ∆ABC ∼ ∆DEF

$∴ \frac{A B}{D E} = \frac{B C}{E F} \Rightarrow \frac{1}{2} = \frac{6}{E F} \Rightarrow E F = 12 cm$

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If ∆ABC ∼ ∆DEF such that 2 AB = DE and BC = 6 cm, find EF.

∵ ∆ABC ∼ ∆DEF ∴ ABDE = BCEF⇒ 12 = 6EF⇒ EF = 12 cm

$∵$ ∆ABC ∼ ∆DEF

$∴ \frac{A B}{D E} = \frac{B C}{E F} \Rightarrow \frac{1}{2} = \frac{6}{E F} \Rightarrow E F = 12 cm$