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Question

If ABC is an isosceles triangle and D is a point of BC such that AD ⊥ BC, then

(a) AB2 − AD2 = BD.DC
(b) AB2 − AD2 = BD2 − DC2
(c) AB2 + AD2 = BD.DC
(d) AB2 + AD2 = BD2 − DC2

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Solution

Given: ΔABC is an isosceles triangle, D is a point on BC such that

We know that in an isosceles triangle the perpendicular from the vertex bisects the base.

∴ BD = DC

Applying Pythagoras theorem in ΔABD

Since

Hence correct answer is .


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