Question

IF ABC is an isosceles triangle right angled at C, then $\tan (A-B)$ is

• A. 0
• B. 1
• C. $\infty$
• D. -1

Answer 1

The correct option is A 0

In an isosceles triangle ABC right angled at C
.$\angle A=\angle B={45}^{\circ }$
therefore $\angle A-\angle B-0^{\circ }$
$\therefore \tan (A-B)=\tan 0^{\circ }=0$