Question

If ABC is an isosceles triangle right angled at C, then tan (A - B) is

• A. 0
• B. 1
• C. $\infty$
• D. -1

Answer 1

The correct option is A 0

Since triangle ABC is a isosceles triangle right angled at C
$C={90}^{0}andA=B$
$A+B+C={180}^0$
$A+B+{90}^0={180}^0$
$2A={90}^0$
$A=B={45}^0$
Therefore
$\tan (A-B)$
$=\tan ({45}^0-{45}^0)$
$=\tan 0^0=0$
Hence answer is A