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Question

If △ABC ≅ △PQR by SSS congruency and ∠A = 76°, then what is the ​sum of the measures of ∠Q and ∠R in △PQR?​


A

76°​

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B

104°​

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C

38°​

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D

52°​

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Solution

The correct option is B

104°​


In △ABC,
∠A = 76° (Given)
∠A + ∠B + ∠C = 180°
(Angle sum property of triangle)
∠B + ∠C = 180° - 76° = 104°

It is given that, △ABC ≅ △PQR
So, ∠P = ∠A = 76° (by C.P.C.T.)

Now, in △PQR
∠P + ∠Q + ∠R = 180°
(Angle sum property of triangle)
∠Q + ∠R = 180° - 76° = 104°


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