If ABCD is a cyclic quadrilateral and - A -90- x - then - C -A- 900-x 0B- 900-x 0C- 1800 - xoD- 900- 02

The correct option is A 90o+xoIn the cyclic quadrilateral ABCD, ∠ A + ∠ C = 180^∘ ∠ A = 90^∘ x^∘ ∠ C = 180 (90 x) =180 90 + x = 90^∘ + x^∘ ...

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Cyclic Quadrilateral

If ABCD is a ...

Question

If ABCD is a cyclic quadrilateral and $∠ A = 90^{\circ} - x^{\circ}$ , then $∠ C =$

90o+xo

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90o - xo

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180o - xo

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90o + xo2

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Solution

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∠ A = 90^{\circ} - x^{\circ}

∠ C =

A B C D, ∠ B = 90^{0}

∠ D = 90^{0}

2 A C^{2} - A B^{2} = B C^{2} + C D^{2} + D A^{2}

A B C D

∠ B = 90

{A D}^{2} = {A B}^{2} + {B C}^{2} + {C D}^{2}

∠ A C D = 90^{0}

∠ B = 90^{0}, ∠ C - ∠ D = 60^{0}

∠ A - ∠ C - ∠ D = 10^{0}

∠ A, ∠ C, ∠ D

∠ A + ∠ D = 90^{0}

B D^{2} + A C^{2} = A D^{2} + B C^{2}

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