Question

If ABCD is a cyclic quadrilateral and $\angle A={90}^{\circ }-x^{\circ }$ , then $\angle C=$

• A. 90o+xo
• B. 90o - xo
• C. 180o - xo
• D. 90o + xo2

Answer 1

The correct option is A 90o+xo

In the cyclic quadrilateral ABCD, $\angle A+\angle C={180}^{\circ }$
$\angle A={90}^{\circ }-x^{\circ }$
$\angle C=180°-(90-x)$
$=180°-90°+x={90}^{\circ }+x^{\circ }$