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Question

If ABCD is a cyclic quadrilateral with AB as the diameter of the circle and ACD=50, then BAD = ___.


A

70

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B

80

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C

50

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D

40

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Solution

The correct option is D

40


Since an angle in a semicircle is a right angle, ACB=90.
But, BCD=ACD+ACB=50+90=140.
Consider the cyclic quadrilateral ABCD. Since opposite angles are supplementary,
BCD+DAB=180.
BAD=180140=40


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