If ABCD is a parallelogram and BEFC is a square which of the following is true?
True
∠ABE=∠DCF
EF=AD
Given: ABCD is a parallelogram and BEFC is a square.
Consider △ABE and △DCF
AB = DC [Opposite sides of a parallogram]
BE = CF [Sides of a square]
∠ABE=∠DCF [By geometry]
∴△ABE≅△DCF [SAS axiom on congruency]
EF = BC [Sides of a square]
BC = AD [Opposite sides of a parallelogram]
Therefore EF = AD