Question

If ABCD is a square of 28 cm and APD and BPC are semi-circles, the area of shaded region in the given figure is .

• A. $250c{m}^2$
• B. $170c{m}^2$
• C. $200c{m}^2$
• D. $168c{m}^2$

Answer 1

The correct option is D $168c{m}^2$


Side of square = 28 cm
$⟹$ Diameter of a semicircle = 28 cm
$⟹$ Radius of a semicircle = 14 cm
Now,
Area of shaded region = Area of square - Area of two semicircles
=$(28\times 28)-(\frac{22}{7}\times 14\times 14)$
$=784-616=168c{m}^2$