If ABCDEF is a regular hexagon- prove that A-B- -A-C- -A-E- -A-F- -2A-D- -

( AB + AE #160; ) +( AC + AF #160; ) =( DE + AE #160; ) +( AC + DC #160; ) = AD + AD =2 AD ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Rhombus

If ABCDEF i...

Question

If $A B C D E F$ is a regular hexagon. prove that $\to A B - -- - + \to A C - -- - + \to A E - -- - + \to A F - -- - = 2 \to A D - -- - .$

Open in App

Solution

Suggest Corrections

Similar questions

A B C D E F

\to A E +

\to A B =

\to A C

\to A F

A B C D E F

\to A B + \to A C + \to A D + \to A E + \to A F = λ \to A D

λ =

A B C D E F

\to A B + \to A C + \to A D + \to A E + \to A F = k \to A D

k

A B C D E F

O

\to A B, \to A C, \to A D, \to A E, \to A F

A

A B C D E F

A B C D E F

O

\to A B

\to A C

\to A D, \to A E, \to A F

Join BYJU'S Learning Program