If ABCDEF is a regular hexagon- prove that A-B- -A-C- -A-E- -A-F- -2A-D- -

( AB + AE #160; ) +( AC + AF #160; ) =( DE + AE #160; ) +( AC + DC #160; ) = AD + AD =2 AD ...

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If ABCDEF i...

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If $A B C D E F$ is a regular hexagon. prove that $\to A B - -- - + \to A C - -- - + \to A E - -- - + \to A F - -- - = 2 \to A D - -- - .$

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