If AC and BD are two chords of a circle that bisect each other, then quadrilateral ABCD is a

rectangle

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square

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trapezium

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parallelogram

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Solution

The correct option is A rectangle
The two chord must be diameters.
Angle in a semicircle measures $90$ . Therefore
$∠ a = ∠ b = ∠ c = ∠ d = 90$ ,
Therefore, ABCD is a rectangle

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AC and BD are chords of a circle which bisect each other. Prove that (i) AC and BD are diameters; (ii) ABCD is a rectangle.

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