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Question

If ac>b2, then the sum of the coefficients in the expansion of (aα2x2+2bαx+c)n is ,where a,b,c αR and nN

A
positive if a>0
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B
positive if c>0
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C
negative if a<0 and n is odd
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D
positive if c<0 and n is even
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Solution

The correct option is A positive if a>0
We have
(aα2+2bαx+c)n
Sum of coefficients =(aα2+2bα+c)n
aα2+2bα+c
D<0
if a<0 n odd
aα2+2bα+c>0
(aα2+2bα+c)n>0
ifa<0nodd
aα2+2bα+c<0
(aα2+2bα+c)n<0
Hence,
Option (A) is correct answer.

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