If A c of NH 4 OH is 11-5 W -1 cm 2 mol -1 and A cat infinite dilution of NH 4 OH is 0-4876 W -1 cm 2 mol -1- its degree of dissociation is-A- 0-0848B- 0-0424C- 0-058D- 0-157

The correct option is B 0.0424The degree of dissociation is given by, α = ˄^∞_mol/˄^c_mol = 0.4876/11.5 = 0.0424 So, the degree of dissociation is equal to 0. ...

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Standard X

Chemistry

Zinc Ion

If A c of NH ...

Question

If A_c of NH₄OH is 11.5 W^-1cm² mol^-1 andA_cat infinite dilution of NH₄OH is 0.4876 W^-1cm² mol^-1, its degree of dissociation is:

0.157

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0.058

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0.0424

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0.0848

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Solution

The correct option is C
0.0424

The degree of dissociation is given by,
$α = \frac{˄_{m o l}^{\infty}}{˄_{m o l}^{c}} = \frac{0.4876}{11.5} = 0.0424$
So, the degree of dissociation is equal to 0.0424.

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The molar conductance of $N H_{4} O H$ at 0.01 M concentration is 11.3 $o h m^{- 1} c m^{2} m o l^{- 1}$ . The degree of dissociation of $N H_{4} O H$ is: (Molar conductance at infinite dilution = 271.1 $o h m^{- 1} c m^{2} m o l^{- 1}$

Q. The molar conductance of

N H_{4} O H

at 0.01M concentration is 11.3

o h m^{- 1} c m^{2} m o l^{- 1}

. The degree of dissociation
of

N H_{4} O H

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(molar conductance at infinite dilution is 271.1)

Q. If

Λ_{c}

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N H_{4} O H

is 11.5

o h m^{- 1} c m^{2} m o l^{- 1}

, its degree of dissociation would be
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λ^{\circ} O H^{-}

= 197.6

o h m^{- 1} c m^{2} m o l^{- 1}

)

Q. The molar conductance of

N H_{4} O H

at 0.01M concentration is 11.3

o h m^{- 1} c m^{2} m o l^{- 1}

. The degree of dissociation
of

N H_{4} O H

is
(molar conductance at infinite dilution is 271.1)

If $\land_{c} o f N H_{4} O H i s 11.5 Ω^{- 1} c m^{2} m o l^{- 1}$ , its degree of dissociation would be:

(Given $λ_{N H_{4}^{+}}^{\infty} = 73.4 Ω^{- 1} c m^{2} m o l^{- 1}$ and $λ_{O H^{-}}^{\infty} = 197.6 Ω^{- 1} c m^{2} m o l^{- 1}$ ) :

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If Ac of NH4OH is 11.5 W-1cm2 mol-1 and Acat infinite dilution of NH4OH is 0.4876 W-1cm2 mol-1, its degree of dissociation is:

The correct option is C 0.0424The degree of dissociation is given by, α=˄∞mol˄cmol=0.487611.5=0.0424 So, the degree of dissociation is equal to 0.0424.

If A_c of NH₄OH is 11.5 W^-1cm² mol^-1 andA_cat infinite dilution of NH₄OH is 0.4876 W^-1cm² mol^-1, its degree of dissociation is:

The correct option is C
0.0424

The degree of dissociation is given by,
$α = \frac{˄_{m o l}^{\infty}}{˄_{m o l}^{c}} = \frac{0.4876}{11.5} = 0.0424$
So, the degree of dissociation is equal to 0.0424.