CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If accelaration of A is 2m/s2 which is smaller than accelaration of B then the value of frictional force applied byon A is
1164499_175d5a7ebb2b415f8d2bc1d82d8d71c2.PNG

Open in App
Solution

Solution
REF.Image
The ABD of the system will be as: aA=2m/s2
Then,
fs=mAaA
ffs=mBaB
As mA=5kg and aA=2m/s2
fs=(5)(2)=10N
So, frictional force applied
will be 10 N on A.
Note : fs can be equal or greater
then fs depending upon the surface.

1143204_1164499_ans_332263f4725b4b10910c2e7395a80478.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Motion: A Need for Speed
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon